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DataAnalyticsquiz.xlsx
DataAnalyticsquiz.xlsx
Ex 1 and 2
N of observation | Package size in grams | |||||
1 | 984 | |||||
2 | 1037 | |||||
3 | 1017 | Exercise 1 | (30 points) | |||
4 | 1012 | You are producing cornflakes and there is a new law that requires you to publish on the package 99% confidence interval for the weight of the cornflakes pack. | ||||
5 | 1012 | Assume that population standard deviation (aka sigma) is known and equal to 25 grams. | ||||
6 | 1041 | Construct 99% confidence interval and briefly interpret it with 1-2 sentences. | ||||
7 | 980 | |||||
8 | 1028 | Exercise 2 | (30 points) | |||
9 | 960 | You are producing cornflakes and there is a new law that requires you to publish on the package 99% confidence interval for the weight of the cornflakes pack. | ||||
10 | 1032 | Assume that population standard deviation is not known and you need to estimate it using the sample data. | ||||
11 | 981 | Construct 95% confidence interval and briefly interpret it with 1-2 sentences | ||||
12 | 982 | |||||
13 | 1016 | |||||
14 | 972 | |||||
15 | 982 | |||||
16 | 986 | |||||
17 | 1018 | |||||
18 | 1047 | |||||
19 | 964 | |||||
20 | 969 | |||||
21 | 972 | |||||
22 | 1018 | |||||
23 | 1005 | |||||
24 | 969 | |||||
25 | 975 | |||||
26 | 1004 | |||||
27 | 987 | |||||
28 | 1026 | |||||
29 | 966 | |||||
30 | 952 | |||||
31 | 1009 | |||||
32 | 997 | |||||
33 | 974 | |||||
34 | 959 | |||||
35 | 1001 | |||||
36 | 1012 | |||||
37 | 1039 | |||||
38 | 1037 | |||||
39 | 993 | |||||
40 | 964 | |||||
41 | 951 | |||||
42 | 987 | |||||
43 | 977 | |||||
44 | 961 | |||||
45 | 1029 | |||||
46 | 1015 | |||||
47 | 954 | |||||
48 | 1004 | |||||
49 | 985 | |||||
50 | 1035 | |||||
51 | 978 | |||||
52 | 1008 | |||||
53 | 1026 | |||||
54 | 1042 | |||||
55 | 980 | |||||
56 | 1049 | |||||
57 | 1025 | |||||
58 | 1029 | |||||
59 | 1007 | |||||
60 | 1048 | |||||
61 | 979 | |||||
62 | 968 | |||||
63 | 973 | |||||
64 | 1020 | |||||
65 | 976 | |||||
66 | 1013 | |||||
67 | 1009 | |||||
68 | 968 | |||||
69 | 1033 | |||||
70 | 970 | |||||
71 | 954 | |||||
72 | 1011 | |||||
73 | 952 | |||||
74 | 1026 | |||||
75 | 1027 | |||||
76 | 1002 | |||||
77 | 1004 | |||||
78 | 963 | |||||
79 | 1034 | |||||
80 | 1034 | |||||
81 | 957 | |||||
82 | 1013 | |||||
83 | 965 | |||||
84 | 954 | |||||
85 | 976 | |||||
86 | 950 | |||||
87 | 951 | |||||
88 | 996 | |||||
89 | 1037 | |||||
90 | 996 | |||||
91 | 1041 | |||||
92 | 951 | |||||
93 | 998 | |||||
94 | 1036 | |||||
95 | 1041 | |||||
96 | 1050 | |||||
97 | 996 | |||||
98 | 1039 | |||||
99 | 1000 | |||||
100 | 959 |
Ex 3
N of observation | Price per liter of gasoline, EUR | |||||
1 | 1.8 | |||||
2 | 1.66 | Exercise 3 | (40 points) | |||
3 | 1.73 | The prime minister of one european country said that the average gasoline price in his country is 1.7 EUR. | ||||
4 | 1.76 | His opponents claim that the true (population) gasoline price is higher than 1.7 EUR due to elevated inflation. | ||||
5 | 1.82 | Assume the population standard deviation is known and it is 0.06 EUR. | ||||
6 | 1.78 | Test the null hypothesis that the population average (mu) gasoline price is 1.7 | ||||
7 | 1.7 | against one-sided alternative that population average gasoline price is bigger than 1.7 EUR. | ||||
8 | 1.75 | Use alpha=0.01 and critical value approach. | ||||
9 | 1.82 | Interpret the result in 1-2 sentences. | ||||
10 | 1.83 | |||||
11 | 1.82 | |||||
12 | 1.85 | |||||
13 | 1.78 | |||||
14 | 1.68 | |||||
15 | 1.82 | |||||
16 | 1.71 | |||||
17 | 1.82 | |||||
18 | 1.67 | |||||
19 | 1.8 | |||||
20 | 1.74 | |||||
21 | 1.69 | |||||
22 | 1.65 | |||||
23 | 1.77 | |||||
24 | 1.74 | |||||
25 | 1.78 | |||||
26 | 1.67 | |||||
27 | 1.76 | |||||
28 | 1.8 | |||||
29 | 1.78 | |||||
30 | 1.74 | |||||
31 | 1.69 | |||||
32 | 1.83 | |||||
33 | 1.72 | |||||
34 | 1.76 | |||||
35 | 1.82 | |||||
36 | 1.74 |
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